Question 67.

At the end of the trading day a newsagency has a number of notes in the till. They are: a) What was the amount collected in notes?
b) $43.75 was collected in coins; in total how much was collected altogether? Explanation of answer: Step 1: To find out the answer for a) you must find out the totals of all the notes. 2 x$100 = $200, 3 x$50 = $150, 1 x$20 = $20, 4 x$10 = $40, 5 x$5 = $25. Step 2: Then add them together:$200 + $150 +$20 + $40 +$25 = $435. This gives you the answer for a) Step 3: Now that you know the amount for notes, you can add the coins to the notes to get the answer for b). This is:$435 + $43.75 =$478.75. This is the answer for b)

Question 80. Rose and her four friends went out for lunch.

The total bill for the lunch was $67.20. Rose was the only one to have a cup of coffee. She paid$4 for her coffee and the rest of the bill was shared equally.

Which expression shows the total amount of money Rose paid for her lunch?

Complete correctly:

The total amount Rose paid for her lunch is equal to:

Step 1: To complete this answer you must use the order of operations acronym BIMDAS (brackets, indices, multiplication, division, addition and subtraction) step by step to find the answer. We do not need to know the value amount of the meal and coffee only the expression which would lead us to the final cost.

Step 2: To figure out how much it costs Rose for her meal we must break the bill into sections. If the total bill costs $67.20, we must subtract$4 from it to determine the portion that is to be shared. This is the first step and is represented by (67.2 – 4).

Step 3: The next step requires use to divide the shared portion between the 5 friends. This would be represented by ÷ 5 in the equation.

Step 4: The next step would be add the value of the coffee back onto Rose’s amount. This would be represented by + 4 in the equation.

Step 5: We add all the components together to give the final equation of: (67.20 – 4) ÷ 5 + 4

Step 6: The correct answer is – d) (67.20 – 4) ÷ 5 + 4.

Question 85. A 10 kilometre section of highway is to be resurfaced.

The highway is straight and is 6.3 metres wide.

How many square metres of the road need to be resurfaced?